Solution Code
Java
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode() {}
* ListNode(int val) { this.val = val; }
* ListNode(int val, ListNode next) { this.val = val; this.next = next; }
* }
*/
class Solution {
public ListNode mergeTwoLists(ListNode list1, ListNode list2) {
if (list1 == null) {
return list2;
}
if (list2 == null) {
return list1;
}
ListNode mergedHead = null;
ListNode temporaryHead = null;
while (list1 != null || list2 != null) {
if (list1 == null && list2 != null) {
ListNode node = new ListNode(list2.val);
if (mergedHead == null) {
mergedHead = node;
} else {
temporaryHead.next = node;
}
temporaryHead = node;
list2 = list2.next;
} else if (list1 != null && list2 == null) {
ListNode node = new ListNode(list1.val);
if (mergedHead == null) {
mergedHead = node;
} else {
temporaryHead.next = node;
}
temporaryHead = node;
list1 = list1.next;
} else {
if (list1.val < list2.val) {
ListNode node = new ListNode(list1.val);
if (mergedHead == null) {
mergedHead = node;
} else {
temporaryHead.next = node;
}
temporaryHead = node;
list1 = list1.next;
} else {
ListNode node = new ListNode(list2.val);
if (mergedHead == null) {
mergedHead = node;
} else {
temporaryHead.next = node;
}
temporaryHead = node;
list2 = list2.next;
}
}
}
return mergedHead;
}
}